3.1349 \(\int \cos ^{\frac{9}{2}}(c+d x) (a+b \sec (c+d x))^{5/2} (A+B \sec (c+d x)+C \sec ^2(c+d x)) \, dx\)
Optimal. Leaf size=452 \[ -\frac{2 \left (a^2-b^2\right ) \left (-6 a^2 b (19 A+28 C)-75 a^3 B-45 a b^2 B+10 A b^3\right ) \sqrt{\frac{a \cos (c+d x)+b}{a+b}} \text{EllipticF}\left (\frac{1}{2} (c+d x),\frac{2 a}{a+b}\right )}{315 a^2 d \sqrt{\cos (c+d x)} \sqrt{a+b \sec (c+d x)}}+\frac{2 \sin (c+d x) \cos ^{\frac{3}{2}}(c+d x) \left (7 a^2 (7 A+9 C)+90 a b B+15 A b^2\right ) \sqrt{a+b \sec (c+d x)}}{315 d}+\frac{2 \sin (c+d x) \sqrt{\cos (c+d x)} \left (a^2 b (163 A+231 C)+75 a^3 B+135 a b^2 B+5 A b^3\right ) \sqrt{a+b \sec (c+d x)}}{315 a d}-\frac{2 \sqrt{\cos (c+d x)} \left (-3 a^2 b^2 (93 A+161 C)-21 a^4 (7 A+9 C)-435 a^3 b B-45 a b^3 B+10 A b^4\right ) \sqrt{a+b \sec (c+d x)} E\left (\frac{1}{2} (c+d x)|\frac{2 a}{a+b}\right )}{315 a^2 d \sqrt{\frac{a \cos (c+d x)+b}{a+b}}}+\frac{2 (9 a B+5 A b) \sin (c+d x) \cos ^{\frac{5}{2}}(c+d x) (a+b \sec (c+d x))^{3/2}}{63 d}+\frac{2 A \sin (c+d x) \cos ^{\frac{7}{2}}(c+d x) (a+b \sec (c+d x))^{5/2}}{9 d} \]
[Out]
(-2*(a^2 - b^2)*(10*A*b^3 - 75*a^3*B - 45*a*b^2*B - 6*a^2*b*(19*A + 28*C))*Sqrt[(b + a*Cos[c + d*x])/(a + b)]*
EllipticF[(c + d*x)/2, (2*a)/(a + b)])/(315*a^2*d*Sqrt[Cos[c + d*x]]*Sqrt[a + b*Sec[c + d*x]]) - (2*(10*A*b^4
- 435*a^3*b*B - 45*a*b^3*B - 21*a^4*(7*A + 9*C) - 3*a^2*b^2*(93*A + 161*C))*Sqrt[Cos[c + d*x]]*EllipticE[(c +
d*x)/2, (2*a)/(a + b)]*Sqrt[a + b*Sec[c + d*x]])/(315*a^2*d*Sqrt[(b + a*Cos[c + d*x])/(a + b)]) + (2*(5*A*b^3
+ 75*a^3*B + 135*a*b^2*B + a^2*b*(163*A + 231*C))*Sqrt[Cos[c + d*x]]*Sqrt[a + b*Sec[c + d*x]]*Sin[c + d*x])/(3
15*a*d) + (2*(15*A*b^2 + 90*a*b*B + 7*a^2*(7*A + 9*C))*Cos[c + d*x]^(3/2)*Sqrt[a + b*Sec[c + d*x]]*Sin[c + d*x
])/(315*d) + (2*(5*A*b + 9*a*B)*Cos[c + d*x]^(5/2)*(a + b*Sec[c + d*x])^(3/2)*Sin[c + d*x])/(63*d) + (2*A*Cos[
c + d*x]^(7/2)*(a + b*Sec[c + d*x])^(5/2)*Sin[c + d*x])/(9*d)
________________________________________________________________________________________
Rubi [A] time = 1.91044, antiderivative size = 452, normalized size of antiderivative
= 1., number of steps used = 12, number of rules used = 10, integrand size = 45, \(\frac{\text{number of rules}}{\text{integrand size}}\)
= 0.222, Rules used = {4265, 4094, 4104, 4035, 3856, 2655, 2653, 3858, 2663, 2661}
\[ \frac{2 \sin (c+d x) \cos ^{\frac{3}{2}}(c+d x) \left (7 a^2 (7 A+9 C)+90 a b B+15 A b^2\right ) \sqrt{a+b \sec (c+d x)}}{315 d}+\frac{2 \sin (c+d x) \sqrt{\cos (c+d x)} \left (a^2 b (163 A+231 C)+75 a^3 B+135 a b^2 B+5 A b^3\right ) \sqrt{a+b \sec (c+d x)}}{315 a d}-\frac{2 \left (a^2-b^2\right ) \left (-6 a^2 b (19 A+28 C)-75 a^3 B-45 a b^2 B+10 A b^3\right ) \sqrt{\frac{a \cos (c+d x)+b}{a+b}} F\left (\frac{1}{2} (c+d x)|\frac{2 a}{a+b}\right )}{315 a^2 d \sqrt{\cos (c+d x)} \sqrt{a+b \sec (c+d x)}}-\frac{2 \sqrt{\cos (c+d x)} \left (-3 a^2 b^2 (93 A+161 C)-21 a^4 (7 A+9 C)-435 a^3 b B-45 a b^3 B+10 A b^4\right ) \sqrt{a+b \sec (c+d x)} E\left (\frac{1}{2} (c+d x)|\frac{2 a}{a+b}\right )}{315 a^2 d \sqrt{\frac{a \cos (c+d x)+b}{a+b}}}+\frac{2 (9 a B+5 A b) \sin (c+d x) \cos ^{\frac{5}{2}}(c+d x) (a+b \sec (c+d x))^{3/2}}{63 d}+\frac{2 A \sin (c+d x) \cos ^{\frac{7}{2}}(c+d x) (a+b \sec (c+d x))^{5/2}}{9 d} \]
Antiderivative was successfully verified.
[In]
Int[Cos[c + d*x]^(9/2)*(a + b*Sec[c + d*x])^(5/2)*(A + B*Sec[c + d*x] + C*Sec[c + d*x]^2),x]
[Out]
(-2*(a^2 - b^2)*(10*A*b^3 - 75*a^3*B - 45*a*b^2*B - 6*a^2*b*(19*A + 28*C))*Sqrt[(b + a*Cos[c + d*x])/(a + b)]*
EllipticF[(c + d*x)/2, (2*a)/(a + b)])/(315*a^2*d*Sqrt[Cos[c + d*x]]*Sqrt[a + b*Sec[c + d*x]]) - (2*(10*A*b^4
- 435*a^3*b*B - 45*a*b^3*B - 21*a^4*(7*A + 9*C) - 3*a^2*b^2*(93*A + 161*C))*Sqrt[Cos[c + d*x]]*EllipticE[(c +
d*x)/2, (2*a)/(a + b)]*Sqrt[a + b*Sec[c + d*x]])/(315*a^2*d*Sqrt[(b + a*Cos[c + d*x])/(a + b)]) + (2*(5*A*b^3
+ 75*a^3*B + 135*a*b^2*B + a^2*b*(163*A + 231*C))*Sqrt[Cos[c + d*x]]*Sqrt[a + b*Sec[c + d*x]]*Sin[c + d*x])/(3
15*a*d) + (2*(15*A*b^2 + 90*a*b*B + 7*a^2*(7*A + 9*C))*Cos[c + d*x]^(3/2)*Sqrt[a + b*Sec[c + d*x]]*Sin[c + d*x
])/(315*d) + (2*(5*A*b + 9*a*B)*Cos[c + d*x]^(5/2)*(a + b*Sec[c + d*x])^(3/2)*Sin[c + d*x])/(63*d) + (2*A*Cos[
c + d*x]^(7/2)*(a + b*Sec[c + d*x])^(5/2)*Sin[c + d*x])/(9*d)
Rule 4265
Int[(cos[(a_.) + (b_.)*(x_)]*(c_.))^(m_.)*(u_), x_Symbol] :> Dist[(c*Cos[a + b*x])^m*(c*Sec[a + b*x])^m, Int[A
ctivateTrig[u]/(c*Sec[a + b*x])^m, x], x] /; FreeQ[{a, b, c, m}, x] && !IntegerQ[m] && KnownSecantIntegrandQ[
u, x]
Rule 4094
Int[((A_.) + csc[(e_.) + (f_.)*(x_)]*(B_.) + csc[(e_.) + (f_.)*(x_)]^2*(C_.))*(csc[(e_.) + (f_.)*(x_)]*(d_.))^
(n_)*(csc[(e_.) + (f_.)*(x_)]*(b_.) + (a_))^(m_), x_Symbol] :> Simp[(A*Cot[e + f*x]*(a + b*Csc[e + f*x])^m*(d*
Csc[e + f*x])^n)/(f*n), x] - Dist[1/(d*n), Int[(a + b*Csc[e + f*x])^(m - 1)*(d*Csc[e + f*x])^(n + 1)*Simp[A*b*
m - a*B*n - (b*B*n + a*(C*n + A*(n + 1)))*Csc[e + f*x] - b*(C*n + A*(m + n + 1))*Csc[e + f*x]^2, x], x], x] /;
FreeQ[{a, b, d, e, f, A, B, C}, x] && NeQ[a^2 - b^2, 0] && GtQ[m, 0] && LeQ[n, -1]
Rule 4104
Int[((A_.) + csc[(e_.) + (f_.)*(x_)]*(B_.) + csc[(e_.) + (f_.)*(x_)]^2*(C_.))*(csc[(e_.) + (f_.)*(x_)]*(d_.))^
(n_)*(csc[(e_.) + (f_.)*(x_)]*(b_.) + (a_))^(m_), x_Symbol] :> Simp[(A*Cot[e + f*x]*(a + b*Csc[e + f*x])^(m +
1)*(d*Csc[e + f*x])^n)/(a*f*n), x] + Dist[1/(a*d*n), Int[(a + b*Csc[e + f*x])^m*(d*Csc[e + f*x])^(n + 1)*Simp[
a*B*n - A*b*(m + n + 1) + a*(A + A*n + C*n)*Csc[e + f*x] + A*b*(m + n + 2)*Csc[e + f*x]^2, x], x], x] /; FreeQ
[{a, b, d, e, f, A, B, C, m}, x] && NeQ[a^2 - b^2, 0] && LeQ[n, -1]
Rule 4035
Int[(csc[(e_.) + (f_.)*(x_)]*(B_.) + (A_))/(Sqrt[csc[(e_.) + (f_.)*(x_)]*(d_.)]*Sqrt[csc[(e_.) + (f_.)*(x_)]*(
b_.) + (a_)]), x_Symbol] :> Dist[A/a, Int[Sqrt[a + b*Csc[e + f*x]]/Sqrt[d*Csc[e + f*x]], x], x] - Dist[(A*b -
a*B)/(a*d), Int[Sqrt[d*Csc[e + f*x]]/Sqrt[a + b*Csc[e + f*x]], x], x] /; FreeQ[{a, b, d, e, f, A, B}, x] && Ne
Q[A*b - a*B, 0] && NeQ[a^2 - b^2, 0]
Rule 3856
Int[Sqrt[csc[(e_.) + (f_.)*(x_)]*(b_.) + (a_)]/Sqrt[csc[(e_.) + (f_.)*(x_)]*(d_.)], x_Symbol] :> Dist[Sqrt[a +
b*Csc[e + f*x]]/(Sqrt[d*Csc[e + f*x]]*Sqrt[b + a*Sin[e + f*x]]), Int[Sqrt[b + a*Sin[e + f*x]], x], x] /; Free
Q[{a, b, d, e, f}, x] && NeQ[a^2 - b^2, 0]
Rule 2655
Int[Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Dist[Sqrt[a + b*Sin[c + d*x]]/Sqrt[(a + b*Sin[c +
d*x])/(a + b)], Int[Sqrt[a/(a + b) + (b*Sin[c + d*x])/(a + b)], x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[a^2 -
b^2, 0] && !GtQ[a + b, 0]
Rule 2653
Int[Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2*Sqrt[a + b]*EllipticE[(1*(c - Pi/2 + d*x)
)/2, (2*b)/(a + b)])/d, x] /; FreeQ[{a, b, c, d}, x] && NeQ[a^2 - b^2, 0] && GtQ[a + b, 0]
Rule 3858
Int[Sqrt[csc[(e_.) + (f_.)*(x_)]*(d_.)]/Sqrt[csc[(e_.) + (f_.)*(x_)]*(b_.) + (a_)], x_Symbol] :> Dist[(Sqrt[d*
Csc[e + f*x]]*Sqrt[b + a*Sin[e + f*x]])/Sqrt[a + b*Csc[e + f*x]], Int[1/Sqrt[b + a*Sin[e + f*x]], x], x] /; Fr
eeQ[{a, b, d, e, f}, x] && NeQ[a^2 - b^2, 0]
Rule 2663
Int[1/Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Dist[Sqrt[(a + b*Sin[c + d*x])/(a + b)]/Sqrt[a
+ b*Sin[c + d*x]], Int[1/Sqrt[a/(a + b) + (b*Sin[c + d*x])/(a + b)], x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[a
^2 - b^2, 0] && !GtQ[a + b, 0]
Rule 2661
Int[1/Sqrt[(a_) + (b_.)*sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2*EllipticF[(1*(c - Pi/2 + d*x))/2, (2*b)
/(a + b)])/(d*Sqrt[a + b]), x] /; FreeQ[{a, b, c, d}, x] && NeQ[a^2 - b^2, 0] && GtQ[a + b, 0]
Rubi steps
\begin{align*} \int \cos ^{\frac{9}{2}}(c+d x) (a+b \sec (c+d x))^{5/2} \left (A+B \sec (c+d x)+C \sec ^2(c+d x)\right ) \, dx &=\left (\sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \frac{(a+b \sec (c+d x))^{5/2} \left (A+B \sec (c+d x)+C \sec ^2(c+d x)\right )}{\sec ^{\frac{9}{2}}(c+d x)} \, dx\\ &=\frac{2 A \cos ^{\frac{7}{2}}(c+d x) (a+b \sec (c+d x))^{5/2} \sin (c+d x)}{9 d}+\frac{1}{9} \left (2 \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \frac{(a+b \sec (c+d x))^{3/2} \left (\frac{1}{2} (5 A b+9 a B)+\frac{1}{2} (7 a A+9 b B+9 a C) \sec (c+d x)+\frac{1}{2} b (2 A+9 C) \sec ^2(c+d x)\right )}{\sec ^{\frac{7}{2}}(c+d x)} \, dx\\ &=\frac{2 (5 A b+9 a B) \cos ^{\frac{5}{2}}(c+d x) (a+b \sec (c+d x))^{3/2} \sin (c+d x)}{63 d}+\frac{2 A \cos ^{\frac{7}{2}}(c+d x) (a+b \sec (c+d x))^{5/2} \sin (c+d x)}{9 d}+\frac{1}{63} \left (4 \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \frac{\sqrt{a+b \sec (c+d x)} \left (\frac{1}{4} \left (15 A b^2+90 a b B+7 a^2 (7 A+9 C)\right )+\frac{1}{4} \left (88 a A b+45 a^2 B+63 b^2 B+126 a b C\right ) \sec (c+d x)+\frac{3}{4} b (8 A b+6 a B+21 b C) \sec ^2(c+d x)\right )}{\sec ^{\frac{5}{2}}(c+d x)} \, dx\\ &=\frac{2 \left (15 A b^2+90 a b B+7 a^2 (7 A+9 C)\right ) \cos ^{\frac{3}{2}}(c+d x) \sqrt{a+b \sec (c+d x)} \sin (c+d x)}{315 d}+\frac{2 (5 A b+9 a B) \cos ^{\frac{5}{2}}(c+d x) (a+b \sec (c+d x))^{3/2} \sin (c+d x)}{63 d}+\frac{2 A \cos ^{\frac{7}{2}}(c+d x) (a+b \sec (c+d x))^{5/2} \sin (c+d x)}{9 d}+\frac{1}{315} \left (8 \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \frac{\frac{3}{8} \left (5 A b^3+75 a^3 B+135 a b^2 B+a^2 b (163 A+231 C)\right )+\frac{1}{8} \left (585 a^2 b B+315 b^3 B+21 a^3 (7 A+9 C)+5 a b^2 (121 A+189 C)\right ) \sec (c+d x)+\frac{1}{8} b \left (270 a b B+14 a^2 (7 A+9 C)+15 b^2 (10 A+21 C)\right ) \sec ^2(c+d x)}{\sec ^{\frac{3}{2}}(c+d x) \sqrt{a+b \sec (c+d x)}} \, dx\\ &=\frac{2 \left (5 A b^3+75 a^3 B+135 a b^2 B+a^2 b (163 A+231 C)\right ) \sqrt{\cos (c+d x)} \sqrt{a+b \sec (c+d x)} \sin (c+d x)}{315 a d}+\frac{2 \left (15 A b^2+90 a b B+7 a^2 (7 A+9 C)\right ) \cos ^{\frac{3}{2}}(c+d x) \sqrt{a+b \sec (c+d x)} \sin (c+d x)}{315 d}+\frac{2 (5 A b+9 a B) \cos ^{\frac{5}{2}}(c+d x) (a+b \sec (c+d x))^{3/2} \sin (c+d x)}{63 d}+\frac{2 A \cos ^{\frac{7}{2}}(c+d x) (a+b \sec (c+d x))^{5/2} \sin (c+d x)}{9 d}-\frac{\left (16 \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \frac{\frac{3}{16} \left (10 A b^4-435 a^3 b B-45 a b^3 B-21 a^4 (7 A+9 C)-3 a^2 b^2 (93 A+161 C)\right )-\frac{3}{16} a \left (75 a^3 B+405 a b^2 B+5 b^3 (31 A+63 C)+3 a^2 b (87 A+119 C)\right ) \sec (c+d x)}{\sqrt{\sec (c+d x)} \sqrt{a+b \sec (c+d x)}} \, dx}{945 a}\\ &=\frac{2 \left (5 A b^3+75 a^3 B+135 a b^2 B+a^2 b (163 A+231 C)\right ) \sqrt{\cos (c+d x)} \sqrt{a+b \sec (c+d x)} \sin (c+d x)}{315 a d}+\frac{2 \left (15 A b^2+90 a b B+7 a^2 (7 A+9 C)\right ) \cos ^{\frac{3}{2}}(c+d x) \sqrt{a+b \sec (c+d x)} \sin (c+d x)}{315 d}+\frac{2 (5 A b+9 a B) \cos ^{\frac{5}{2}}(c+d x) (a+b \sec (c+d x))^{3/2} \sin (c+d x)}{63 d}+\frac{2 A \cos ^{\frac{7}{2}}(c+d x) (a+b \sec (c+d x))^{5/2} \sin (c+d x)}{9 d}-\frac{\left (\left (a^2-b^2\right ) \left (10 A b^3-75 a^3 B-45 a b^2 B-6 a^2 b (19 A+28 C)\right ) \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \frac{\sqrt{\sec (c+d x)}}{\sqrt{a+b \sec (c+d x)}} \, dx}{315 a^2}-\frac{\left (\left (10 A b^4-435 a^3 b B-45 a b^3 B-21 a^4 (7 A+9 C)-3 a^2 b^2 (93 A+161 C)\right ) \sqrt{\cos (c+d x)} \sqrt{\sec (c+d x)}\right ) \int \frac{\sqrt{a+b \sec (c+d x)}}{\sqrt{\sec (c+d x)}} \, dx}{315 a^2}\\ &=\frac{2 \left (5 A b^3+75 a^3 B+135 a b^2 B+a^2 b (163 A+231 C)\right ) \sqrt{\cos (c+d x)} \sqrt{a+b \sec (c+d x)} \sin (c+d x)}{315 a d}+\frac{2 \left (15 A b^2+90 a b B+7 a^2 (7 A+9 C)\right ) \cos ^{\frac{3}{2}}(c+d x) \sqrt{a+b \sec (c+d x)} \sin (c+d x)}{315 d}+\frac{2 (5 A b+9 a B) \cos ^{\frac{5}{2}}(c+d x) (a+b \sec (c+d x))^{3/2} \sin (c+d x)}{63 d}+\frac{2 A \cos ^{\frac{7}{2}}(c+d x) (a+b \sec (c+d x))^{5/2} \sin (c+d x)}{9 d}-\frac{\left (\left (a^2-b^2\right ) \left (10 A b^3-75 a^3 B-45 a b^2 B-6 a^2 b (19 A+28 C)\right ) \sqrt{b+a \cos (c+d x)}\right ) \int \frac{1}{\sqrt{b+a \cos (c+d x)}} \, dx}{315 a^2 \sqrt{\cos (c+d x)} \sqrt{a+b \sec (c+d x)}}-\frac{\left (\left (10 A b^4-435 a^3 b B-45 a b^3 B-21 a^4 (7 A+9 C)-3 a^2 b^2 (93 A+161 C)\right ) \sqrt{\cos (c+d x)} \sqrt{a+b \sec (c+d x)}\right ) \int \sqrt{b+a \cos (c+d x)} \, dx}{315 a^2 \sqrt{b+a \cos (c+d x)}}\\ &=\frac{2 \left (5 A b^3+75 a^3 B+135 a b^2 B+a^2 b (163 A+231 C)\right ) \sqrt{\cos (c+d x)} \sqrt{a+b \sec (c+d x)} \sin (c+d x)}{315 a d}+\frac{2 \left (15 A b^2+90 a b B+7 a^2 (7 A+9 C)\right ) \cos ^{\frac{3}{2}}(c+d x) \sqrt{a+b \sec (c+d x)} \sin (c+d x)}{315 d}+\frac{2 (5 A b+9 a B) \cos ^{\frac{5}{2}}(c+d x) (a+b \sec (c+d x))^{3/2} \sin (c+d x)}{63 d}+\frac{2 A \cos ^{\frac{7}{2}}(c+d x) (a+b \sec (c+d x))^{5/2} \sin (c+d x)}{9 d}-\frac{\left (\left (a^2-b^2\right ) \left (10 A b^3-75 a^3 B-45 a b^2 B-6 a^2 b (19 A+28 C)\right ) \sqrt{\frac{b+a \cos (c+d x)}{a+b}}\right ) \int \frac{1}{\sqrt{\frac{b}{a+b}+\frac{a \cos (c+d x)}{a+b}}} \, dx}{315 a^2 \sqrt{\cos (c+d x)} \sqrt{a+b \sec (c+d x)}}-\frac{\left (\left (10 A b^4-435 a^3 b B-45 a b^3 B-21 a^4 (7 A+9 C)-3 a^2 b^2 (93 A+161 C)\right ) \sqrt{\cos (c+d x)} \sqrt{a+b \sec (c+d x)}\right ) \int \sqrt{\frac{b}{a+b}+\frac{a \cos (c+d x)}{a+b}} \, dx}{315 a^2 \sqrt{\frac{b+a \cos (c+d x)}{a+b}}}\\ &=-\frac{2 \left (a^2-b^2\right ) \left (10 A b^3-75 a^3 B-45 a b^2 B-6 a^2 b (19 A+28 C)\right ) \sqrt{\frac{b+a \cos (c+d x)}{a+b}} F\left (\frac{1}{2} (c+d x)|\frac{2 a}{a+b}\right )}{315 a^2 d \sqrt{\cos (c+d x)} \sqrt{a+b \sec (c+d x)}}-\frac{2 \left (10 A b^4-435 a^3 b B-45 a b^3 B-21 a^4 (7 A+9 C)-3 a^2 b^2 (93 A+161 C)\right ) \sqrt{\cos (c+d x)} E\left (\frac{1}{2} (c+d x)|\frac{2 a}{a+b}\right ) \sqrt{a+b \sec (c+d x)}}{315 a^2 d \sqrt{\frac{b+a \cos (c+d x)}{a+b}}}+\frac{2 \left (5 A b^3+75 a^3 B+135 a b^2 B+a^2 b (163 A+231 C)\right ) \sqrt{\cos (c+d x)} \sqrt{a+b \sec (c+d x)} \sin (c+d x)}{315 a d}+\frac{2 \left (15 A b^2+90 a b B+7 a^2 (7 A+9 C)\right ) \cos ^{\frac{3}{2}}(c+d x) \sqrt{a+b \sec (c+d x)} \sin (c+d x)}{315 d}+\frac{2 (5 A b+9 a B) \cos ^{\frac{5}{2}}(c+d x) (a+b \sec (c+d x))^{3/2} \sin (c+d x)}{63 d}+\frac{2 A \cos ^{\frac{7}{2}}(c+d x) (a+b \sec (c+d x))^{5/2} \sin (c+d x)}{9 d}\\ \end{align*}
Mathematica [C] time = 24.8359, size = 3785, normalized size = 8.37 \[ \text{Result too large to show} \]
Warning: Unable to verify antiderivative.
[In]
Integrate[Cos[c + d*x]^(9/2)*(a + b*Sec[c + d*x])^(5/2)*(A + B*Sec[c + d*x] + C*Sec[c + d*x]^2),x]
[Out]
(Cos[c + d*x]^(9/2)*(a + b*Sec[c + d*x])^(5/2)*(A + B*Sec[c + d*x] + C*Sec[c + d*x]^2)*(((747*a^2*A*b + 20*A*b
^3 + 345*a^3*B + 540*a*b^2*B + 924*a^2*b*C)*Sin[c + d*x])/(315*a) + ((133*a^2*A + 150*A*b^2 + 270*a*b*B + 126*
a^2*C)*Sin[2*(c + d*x)])/315 + (a*(19*A*b + 9*a*B)*Sin[3*(c + d*x)])/63 + (a^2*A*Sin[4*(c + d*x)])/18))/(d*(b
+ a*Cos[c + d*x])^2*(A + 2*C + 2*B*Cos[c + d*x] + A*Cos[2*c + 2*d*x])) - (4*Cos[c + d*x]^(3/2)*((14*a^3*A*Sqrt
[Cos[c + d*x]])/(15*Sqrt[b + a*Cos[c + d*x]]*Sqrt[Sec[c + d*x]]) + (62*a*A*b^2*Sqrt[Cos[c + d*x]])/(35*Sqrt[b
+ a*Cos[c + d*x]]*Sqrt[Sec[c + d*x]]) - (4*A*b^4*Sqrt[Cos[c + d*x]])/(63*a*Sqrt[b + a*Cos[c + d*x]]*Sqrt[Sec[c
+ d*x]]) + (58*a^2*b*B*Sqrt[Cos[c + d*x]])/(21*Sqrt[b + a*Cos[c + d*x]]*Sqrt[Sec[c + d*x]]) + (2*b^3*B*Sqrt[C
os[c + d*x]])/(7*Sqrt[b + a*Cos[c + d*x]]*Sqrt[Sec[c + d*x]]) + (6*a^3*C*Sqrt[Cos[c + d*x]])/(5*Sqrt[b + a*Cos
[c + d*x]]*Sqrt[Sec[c + d*x]]) + (46*a*b^2*C*Sqrt[Cos[c + d*x]])/(15*Sqrt[b + a*Cos[c + d*x]]*Sqrt[Sec[c + d*x
]]) + (58*a^2*A*b*Sqrt[Cos[c + d*x]]*Sqrt[Sec[c + d*x]])/(35*Sqrt[b + a*Cos[c + d*x]]) + (62*A*b^3*Sqrt[Cos[c
+ d*x]]*Sqrt[Sec[c + d*x]])/(63*Sqrt[b + a*Cos[c + d*x]]) + (10*a^3*B*Sqrt[Cos[c + d*x]]*Sqrt[Sec[c + d*x]])/(
21*Sqrt[b + a*Cos[c + d*x]]) + (18*a*b^2*B*Sqrt[Cos[c + d*x]]*Sqrt[Sec[c + d*x]])/(7*Sqrt[b + a*Cos[c + d*x]])
+ (34*a^2*b*C*Sqrt[Cos[c + d*x]]*Sqrt[Sec[c + d*x]])/(15*Sqrt[b + a*Cos[c + d*x]]) + (2*b^3*C*Sqrt[Cos[c + d*
x]]*Sqrt[Sec[c + d*x]])/Sqrt[b + a*Cos[c + d*x]])*(Cos[(c + d*x)/2]^2*Sec[c + d*x])^(3/2)*(a + b*Sec[c + d*x])
^(5/2)*(A + B*Sec[c + d*x] + C*Sec[c + d*x]^2)*((-I)*(a + b)*(-10*A*b^4 + 435*a^3*b*B + 45*a*b^3*B + 21*a^4*(7
*A + 9*C) + 3*a^2*b^2*(93*A + 161*C))*EllipticE[I*ArcSinh[Tan[(c + d*x)/2]], (-a + b)/(a + b)]*Sec[(c + d*x)/2
]^2*Sqrt[((b + a*Cos[c + d*x])*Sec[(c + d*x)/2]^2)/(a + b)] + I*a*(a + b)*(-10*A*b^3 + 6*a^2*b*(19*A + 60*B +
28*C) + 3*a^3*(49*A + 25*B + 63*C) + 15*a*b^2*(11*A + 3*(B + 7*C)))*EllipticF[I*ArcSinh[Tan[(c + d*x)/2]], (-a
+ b)/(a + b)]*Sec[(c + d*x)/2]^2*Sqrt[((b + a*Cos[c + d*x])*Sec[(c + d*x)/2]^2)/(a + b)] + (10*A*b^4 - 435*a^
3*b*B - 45*a*b^3*B - 21*a^4*(7*A + 9*C) - 3*a^2*b^2*(93*A + 161*C))*(b + a*Cos[c + d*x])*(Sec[(c + d*x)/2]^2)^
(3/2)*Tan[(c + d*x)/2]))/(315*a^2*d*(b + a*Cos[c + d*x])^3*(A + 2*C + 2*B*Cos[c + d*x] + A*Cos[2*c + 2*d*x])*S
ec[c + d*x]^(9/2)*((-2*Cos[c + d*x]^(3/2)*(Cos[(c + d*x)/2]^2*Sec[c + d*x])^(3/2)*Sin[c + d*x]*((-I)*(a + b)*(
-10*A*b^4 + 435*a^3*b*B + 45*a*b^3*B + 21*a^4*(7*A + 9*C) + 3*a^2*b^2*(93*A + 161*C))*EllipticE[I*ArcSinh[Tan[
(c + d*x)/2]], (-a + b)/(a + b)]*Sec[(c + d*x)/2]^2*Sqrt[((b + a*Cos[c + d*x])*Sec[(c + d*x)/2]^2)/(a + b)] +
I*a*(a + b)*(-10*A*b^3 + 6*a^2*b*(19*A + 60*B + 28*C) + 3*a^3*(49*A + 25*B + 63*C) + 15*a*b^2*(11*A + 3*(B + 7
*C)))*EllipticF[I*ArcSinh[Tan[(c + d*x)/2]], (-a + b)/(a + b)]*Sec[(c + d*x)/2]^2*Sqrt[((b + a*Cos[c + d*x])*S
ec[(c + d*x)/2]^2)/(a + b)] + (10*A*b^4 - 435*a^3*b*B - 45*a*b^3*B - 21*a^4*(7*A + 9*C) - 3*a^2*b^2*(93*A + 16
1*C))*(b + a*Cos[c + d*x])*(Sec[(c + d*x)/2]^2)^(3/2)*Tan[(c + d*x)/2]))/(315*a*(b + a*Cos[c + d*x])^(3/2)) +
(2*Sqrt[Cos[c + d*x]]*(Cos[(c + d*x)/2]^2*Sec[c + d*x])^(3/2)*Sin[c + d*x]*((-I)*(a + b)*(-10*A*b^4 + 435*a^3*
b*B + 45*a*b^3*B + 21*a^4*(7*A + 9*C) + 3*a^2*b^2*(93*A + 161*C))*EllipticE[I*ArcSinh[Tan[(c + d*x)/2]], (-a +
b)/(a + b)]*Sec[(c + d*x)/2]^2*Sqrt[((b + a*Cos[c + d*x])*Sec[(c + d*x)/2]^2)/(a + b)] + I*a*(a + b)*(-10*A*b
^3 + 6*a^2*b*(19*A + 60*B + 28*C) + 3*a^3*(49*A + 25*B + 63*C) + 15*a*b^2*(11*A + 3*(B + 7*C)))*EllipticF[I*Ar
cSinh[Tan[(c + d*x)/2]], (-a + b)/(a + b)]*Sec[(c + d*x)/2]^2*Sqrt[((b + a*Cos[c + d*x])*Sec[(c + d*x)/2]^2)/(
a + b)] + (10*A*b^4 - 435*a^3*b*B - 45*a*b^3*B - 21*a^4*(7*A + 9*C) - 3*a^2*b^2*(93*A + 161*C))*(b + a*Cos[c +
d*x])*(Sec[(c + d*x)/2]^2)^(3/2)*Tan[(c + d*x)/2]))/(105*a^2*Sqrt[b + a*Cos[c + d*x]]) - (4*Cos[c + d*x]^(3/2
)*(Cos[(c + d*x)/2]^2*Sec[c + d*x])^(3/2)*(((10*A*b^4 - 435*a^3*b*B - 45*a*b^3*B - 21*a^4*(7*A + 9*C) - 3*a^2*
b^2*(93*A + 161*C))*(b + a*Cos[c + d*x])*(Sec[(c + d*x)/2]^2)^(5/2))/2 - I*(a + b)*(-10*A*b^4 + 435*a^3*b*B +
45*a*b^3*B + 21*a^4*(7*A + 9*C) + 3*a^2*b^2*(93*A + 161*C))*EllipticE[I*ArcSinh[Tan[(c + d*x)/2]], (-a + b)/(a
+ b)]*Sec[(c + d*x)/2]^2*Sqrt[((b + a*Cos[c + d*x])*Sec[(c + d*x)/2]^2)/(a + b)]*Tan[(c + d*x)/2] + I*a*(a +
b)*(-10*A*b^3 + 6*a^2*b*(19*A + 60*B + 28*C) + 3*a^3*(49*A + 25*B + 63*C) + 15*a*b^2*(11*A + 3*(B + 7*C)))*Ell
ipticF[I*ArcSinh[Tan[(c + d*x)/2]], (-a + b)/(a + b)]*Sec[(c + d*x)/2]^2*Sqrt[((b + a*Cos[c + d*x])*Sec[(c + d
*x)/2]^2)/(a + b)]*Tan[(c + d*x)/2] - a*(10*A*b^4 - 435*a^3*b*B - 45*a*b^3*B - 21*a^4*(7*A + 9*C) - 3*a^2*b^2*
(93*A + 161*C))*(Sec[(c + d*x)/2]^2)^(3/2)*Sin[c + d*x]*Tan[(c + d*x)/2] + (3*(10*A*b^4 - 435*a^3*b*B - 45*a*b
^3*B - 21*a^4*(7*A + 9*C) - 3*a^2*b^2*(93*A + 161*C))*(b + a*Cos[c + d*x])*(Sec[(c + d*x)/2]^2)^(3/2)*Tan[(c +
d*x)/2]^2)/2 - ((I/2)*(a + b)*(-10*A*b^4 + 435*a^3*b*B + 45*a*b^3*B + 21*a^4*(7*A + 9*C) + 3*a^2*b^2*(93*A +
161*C))*EllipticE[I*ArcSinh[Tan[(c + d*x)/2]], (-a + b)/(a + b)]*Sec[(c + d*x)/2]^2*(-((a*Sec[(c + d*x)/2]^2*S
in[c + d*x])/(a + b)) + ((b + a*Cos[c + d*x])*Sec[(c + d*x)/2]^2*Tan[(c + d*x)/2])/(a + b)))/Sqrt[((b + a*Cos[
c + d*x])*Sec[(c + d*x)/2]^2)/(a + b)] + ((I/2)*a*(a + b)*(-10*A*b^3 + 6*a^2*b*(19*A + 60*B + 28*C) + 3*a^3*(4
9*A + 25*B + 63*C) + 15*a*b^2*(11*A + 3*(B + 7*C)))*EllipticF[I*ArcSinh[Tan[(c + d*x)/2]], (-a + b)/(a + b)]*S
ec[(c + d*x)/2]^2*(-((a*Sec[(c + d*x)/2]^2*Sin[c + d*x])/(a + b)) + ((b + a*Cos[c + d*x])*Sec[(c + d*x)/2]^2*T
an[(c + d*x)/2])/(a + b)))/Sqrt[((b + a*Cos[c + d*x])*Sec[(c + d*x)/2]^2)/(a + b)] - (a*(a + b)*(-10*A*b^3 + 6
*a^2*b*(19*A + 60*B + 28*C) + 3*a^3*(49*A + 25*B + 63*C) + 15*a*b^2*(11*A + 3*(B + 7*C)))*Sec[(c + d*x)/2]^4*S
qrt[((b + a*Cos[c + d*x])*Sec[(c + d*x)/2]^2)/(a + b)])/(2*Sqrt[1 + Tan[(c + d*x)/2]^2]*Sqrt[1 + ((-a + b)*Tan
[(c + d*x)/2]^2)/(a + b)]) + ((a + b)*(-10*A*b^4 + 435*a^3*b*B + 45*a*b^3*B + 21*a^4*(7*A + 9*C) + 3*a^2*b^2*(
93*A + 161*C))*Sec[(c + d*x)/2]^4*Sqrt[((b + a*Cos[c + d*x])*Sec[(c + d*x)/2]^2)/(a + b)]*Sqrt[1 + ((-a + b)*T
an[(c + d*x)/2]^2)/(a + b)])/(2*Sqrt[1 + Tan[(c + d*x)/2]^2])))/(315*a^2*Sqrt[b + a*Cos[c + d*x]]) - (2*Cos[c
+ d*x]^(3/2)*Sqrt[Cos[(c + d*x)/2]^2*Sec[c + d*x]]*((-I)*(a + b)*(-10*A*b^4 + 435*a^3*b*B + 45*a*b^3*B + 21*a^
4*(7*A + 9*C) + 3*a^2*b^2*(93*A + 161*C))*EllipticE[I*ArcSinh[Tan[(c + d*x)/2]], (-a + b)/(a + b)]*Sec[(c + d*
x)/2]^2*Sqrt[((b + a*Cos[c + d*x])*Sec[(c + d*x)/2]^2)/(a + b)] + I*a*(a + b)*(-10*A*b^3 + 6*a^2*b*(19*A + 60*
B + 28*C) + 3*a^3*(49*A + 25*B + 63*C) + 15*a*b^2*(11*A + 3*(B + 7*C)))*EllipticF[I*ArcSinh[Tan[(c + d*x)/2]],
(-a + b)/(a + b)]*Sec[(c + d*x)/2]^2*Sqrt[((b + a*Cos[c + d*x])*Sec[(c + d*x)/2]^2)/(a + b)] + (10*A*b^4 - 43
5*a^3*b*B - 45*a*b^3*B - 21*a^4*(7*A + 9*C) - 3*a^2*b^2*(93*A + 161*C))*(b + a*Cos[c + d*x])*(Sec[(c + d*x)/2]
^2)^(3/2)*Tan[(c + d*x)/2])*(-(Cos[(c + d*x)/2]*Sec[c + d*x]*Sin[(c + d*x)/2]) + Cos[(c + d*x)/2]^2*Sec[c + d*
x]*Tan[c + d*x]))/(105*a^2*Sqrt[b + a*Cos[c + d*x]])))
________________________________________________________________________________________
Maple [B] time = 1.032, size = 4157, normalized size = 9.2 \begin{align*} \text{output too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
int(cos(d*x+c)^(9/2)*(a+b*sec(d*x+c))^(5/2)*(A+B*sec(d*x+c)+C*sec(d*x+c)^2),x)
[Out]
-2/315/d*((b+a*cos(d*x+c))/cos(d*x+c))^(1/2)*cos(d*x+c)^(1/2)*(cos(d*x+c)+1)^2*(-1+cos(d*x+c))^3*(45*B*((a-b)/
(a+b))^(1/2)*sin(d*x+c)*cos(d*x+c)^3*a^5*(1/(cos(d*x+c)+1))^(3/2)+63*C*((a-b)/(a+b))^(1/2)*cos(d*x+c)^3*a^5*(1
/(cos(d*x+c)+1))^(3/2)*sin(d*x+c)+63*C*((a-b)/(a+b))^(1/2)*cos(d*x+c)^2*a^5*(1/(cos(d*x+c)+1))^(3/2)*sin(d*x+c
)+189*C*((a-b)/(a+b))^(1/2)*cos(d*x+c)*a^5*(1/(cos(d*x+c)+1))^(3/2)*sin(d*x+c)+147*A*((a-b)/(a+b))^(1/2)*sin(d
*x+c)*cos(d*x+c)*a^5*(1/(cos(d*x+c)+1))^(3/2)+35*A*((a-b)/(a+b))^(1/2)*sin(d*x+c)*cos(d*x+c)^5*a^5*(1/(cos(d*x
+c)+1))^(3/2)+147*A*((a-b)/(a+b))^(1/2)*sin(d*x+c)*a^4*b*(1/(cos(d*x+c)+1))^(3/2)+75*B*((a-b)/(a+b))^(1/2)*sin
(d*x+c)*a^4*b*(1/(cos(d*x+c)+1))^(3/2)+435*B*((a-b)/(a+b))^(1/2)*sin(d*x+c)*a^3*b^2*(1/(cos(d*x+c)+1))^(3/2)+1
35*B*((a-b)/(a+b))^(1/2)*sin(d*x+c)*a^2*b^3*(1/(cos(d*x+c)+1))^(3/2)+45*B*((a-b)/(a+b))^(1/2)*sin(d*x+c)*a*b^4
*(1/(cos(d*x+c)+1))^(3/2)+189*C*((a-b)/(a+b))^(1/2)*a^4*b*(1/(cos(d*x+c)+1))^(3/2)*sin(d*x+c)+231*C*((a-b)/(a+
b))^(1/2)*a^3*b^2*(1/(cos(d*x+c)+1))^(3/2)*sin(d*x+c)+483*C*((a-b)/(a+b))^(1/2)*a^2*b^3*(1/(cos(d*x+c)+1))^(3/
2)*sin(d*x+c)+279*A*((a-b)/(a+b))^(1/2)*sin(d*x+c)*a^2*b^3*(1/(cos(d*x+c)+1))^(3/2)+5*A*((a-b)/(a+b))^(1/2)*si
n(d*x+c)*a*b^4*(1/(cos(d*x+c)+1))^(3/2)+49*A*((a-b)/(a+b))^(1/2)*sin(d*x+c)*cos(d*x+c)^2*a^5*(1/(cos(d*x+c)+1)
)^(3/2)+49*A*((a-b)/(a+b))^(1/2)*sin(d*x+c)*cos(d*x+c)^3*a^5*(1/(cos(d*x+c)+1))^(3/2)+45*B*((a-b)/(a+b))^(1/2)
*sin(d*x+c)*(1/(cos(d*x+c)+1))^(3/2)*cos(d*x+c)^4*a^5+75*B*((a-b)/(a+b))^(1/2)*sin(d*x+c)*(1/(cos(d*x+c)+1))^(
3/2)*cos(d*x+c)^2*a^5+75*B*((a-b)/(a+b))^(1/2)*sin(d*x+c)*(1/(cos(d*x+c)+1))^(3/2)*cos(d*x+c)*a^5+35*A*((a-b)/
(a+b))^(1/2)*sin(d*x+c)*cos(d*x+c)^4*a^5*(1/(cos(d*x+c)+1))^(3/2)-10*A*(1/(a+b)*(b+a*cos(d*x+c))/(cos(d*x+c)+1
))^(1/2)*EllipticE((-1+cos(d*x+c))*((a-b)/(a+b))^(1/2)/sin(d*x+c),(-(a+b)/(a-b))^(1/2))*b^5+147*A*EllipticF((-
1+cos(d*x+c))*((a-b)/(a+b))^(1/2)/sin(d*x+c),(-(a+b)/(a-b))^(1/2))*(1/(a+b)*(b+a*cos(d*x+c))/(cos(d*x+c)+1))^(
1/2)*a^5-147*A*(1/(a+b)*(b+a*cos(d*x+c))/(cos(d*x+c)+1))^(1/2)*EllipticE((-1+cos(d*x+c))*((a-b)/(a+b))^(1/2)/s
in(d*x+c),(-(a+b)/(a-b))^(1/2))*a^5-75*B*EllipticF((-1+cos(d*x+c))*((a-b)/(a+b))^(1/2)/sin(d*x+c),(-(a+b)/(a-b
))^(1/2))*(1/(a+b)*(b+a*cos(d*x+c))/(cos(d*x+c)+1))^(1/2)*a^5+189*C*EllipticF((-1+cos(d*x+c))*((a-b)/(a+b))^(1
/2)/sin(d*x+c),(-(a+b)/(a-b))^(1/2))*(1/(a+b)*(b+a*cos(d*x+c))/(cos(d*x+c)+1))^(1/2)*a^5-189*C*(1/(a+b)*(b+a*c
os(d*x+c))/(cos(d*x+c)+1))^(1/2)*EllipticE((-1+cos(d*x+c))*((a-b)/(a+b))^(1/2)/sin(d*x+c),(-(a+b)/(a-b))^(1/2)
)*a^5+294*C*((a-b)/(a+b))^(1/2)*cos(d*x+c)^2*a^4*b*(1/(cos(d*x+c)+1))^(3/2)*sin(d*x+c)+212*A*((a-b)/(a+b))^(1/
2)*sin(d*x+c)*cos(d*x+c)*a^4*b*(1/(cos(d*x+c)+1))^(3/2)+212*A*((a-b)/(a+b))^(1/2)*sin(d*x+c)*cos(d*x+c)^2*a^4*
b*(1/(cos(d*x+c)+1))^(3/2)+170*A*((a-b)/(a+b))^(1/2)*sin(d*x+c)*cos(d*x+c)^2*a^3*b^2*(1/(cos(d*x+c)+1))^(3/2)+
80*A*((a-b)/(a+b))^(1/2)*sin(d*x+c)*cos(d*x+c)^2*a^2*b^3*(1/(cos(d*x+c)+1))^(3/2)+130*A*((a-b)/(a+b))^(1/2)*si
n(d*x+c)*cos(d*x+c)^3*a^4*b*(1/(cos(d*x+c)+1))^(3/2)+170*A*((a-b)/(a+b))^(1/2)*sin(d*x+c)*cos(d*x+c)^3*a^3*b^2
*(1/(cos(d*x+c)+1))^(3/2)+130*A*((a-b)/(a+b))^(1/2)*sin(d*x+c)*cos(d*x+c)^4*a^4*b*(1/(cos(d*x+c)+1))^(3/2)+270
*B*((a-b)/(a+b))^(1/2)*sin(d*x+c)*cos(d*x+c)*a^3*b^2*(1/(cos(d*x+c)+1))^(3/2)-5*A*((a-b)/(a+b))^(1/2)*sin(d*x+
c)*cos(d*x+c)*a*b^4*(1/(cos(d*x+c)+1))^(3/2)+180*B*((a-b)/(a+b))^(1/2)*sin(d*x+c)*cos(d*x+c)^3*a^4*b*(1/(cos(d
*x+c)+1))^(3/2)+442*A*((a-b)/(a+b))^(1/2)*sin(d*x+c)*cos(d*x+c)*a^3*b^2*(1/(cos(d*x+c)+1))^(3/2)+80*A*((a-b)/(
a+b))^(1/2)*sin(d*x+c)*cos(d*x+c)*a^2*b^3*(1/(cos(d*x+c)+1))^(3/2)+180*B*((a-b)/(a+b))^(1/2)*sin(d*x+c)*cos(d*
x+c)*a^2*b^3*(1/(cos(d*x+c)+1))^(3/2)+180*B*((a-b)/(a+b))^(1/2)*sin(d*x+c)*cos(d*x+c)^2*a^4*b*(1/(cos(d*x+c)+1
))^(3/2)+270*B*((a-b)/(a+b))^(1/2)*sin(d*x+c)*cos(d*x+c)^2*a^3*b^2*(1/(cos(d*x+c)+1))^(3/2)+510*B*((a-b)/(a+b)
)^(1/2)*sin(d*x+c)*cos(d*x+c)*a^4*b*(1/(cos(d*x+c)+1))^(3/2)+294*C*((a-b)/(a+b))^(1/2)*cos(d*x+c)*a^4*b*(1/(co
s(d*x+c)+1))^(3/2)*sin(d*x+c)+714*C*((a-b)/(a+b))^(1/2)*cos(d*x+c)*a^3*b^2*(1/(cos(d*x+c)+1))^(3/2)*sin(d*x+c)
+163*A*((a-b)/(a+b))^(1/2)*sin(d*x+c)*a^3*b^2*(1/(cos(d*x+c)+1))^(3/2)-315*C*EllipticF((-1+cos(d*x+c))*((a-b)/
(a+b))^(1/2)/sin(d*x+c),(-(a+b)/(a-b))^(1/2))*(1/(a+b)*(b+a*cos(d*x+c))/(cos(d*x+c)+1))^(1/2)*a^2*b^3-261*A*El
lipticF((-1+cos(d*x+c))*((a-b)/(a+b))^(1/2)/sin(d*x+c),(-(a+b)/(a-b))^(1/2))*(1/(a+b)*(b+a*cos(d*x+c))/(cos(d*
x+c)+1))^(1/2)*a^4*b+435*B*EllipticF((-1+cos(d*x+c))*((a-b)/(a+b))^(1/2)/sin(d*x+c),(-(a+b)/(a-b))^(1/2))*(1/(
a+b)*(b+a*cos(d*x+c))/(cos(d*x+c)+1))^(1/2)*a^4*b-405*B*EllipticF((-1+cos(d*x+c))*((a-b)/(a+b))^(1/2)/sin(d*x+
c),(-(a+b)/(a-b))^(1/2))*(1/(a+b)*(b+a*cos(d*x+c))/(cos(d*x+c)+1))^(1/2)*a^3*b^2+45*B*EllipticF((-1+cos(d*x+c)
)*((a-b)/(a+b))^(1/2)/sin(d*x+c),(-(a+b)/(a-b))^(1/2))*(1/(a+b)*(b+a*cos(d*x+c))/(cos(d*x+c)+1))^(1/2)*a^2*b^3
-435*B*(1/(a+b)*(b+a*cos(d*x+c))/(cos(d*x+c)+1))^(1/2)*EllipticE((-1+cos(d*x+c))*((a-b)/(a+b))^(1/2)/sin(d*x+c
),(-(a+b)/(a-b))^(1/2))*a^4*b+435*B*(1/(a+b)*(b+a*cos(d*x+c))/(cos(d*x+c)+1))^(1/2)*EllipticE((-1+cos(d*x+c))*
((a-b)/(a+b))^(1/2)/sin(d*x+c),(-(a+b)/(a-b))^(1/2))*a^3*b^2-45*B*(1/(a+b)*(b+a*cos(d*x+c))/(cos(d*x+c)+1))^(1
/2)*EllipticE((-1+cos(d*x+c))*((a-b)/(a+b))^(1/2)/sin(d*x+c),(-(a+b)/(a-b))^(1/2))*a^2*b^3+45*B*(1/(a+b)*(b+a*
cos(d*x+c))/(cos(d*x+c)+1))^(1/2)*EllipticE((-1+cos(d*x+c))*((a-b)/(a+b))^(1/2)/sin(d*x+c),(-(a+b)/(a-b))^(1/2
))*a*b^4-357*C*EllipticF((-1+cos(d*x+c))*((a-b)/(a+b))^(1/2)/sin(d*x+c),(-(a+b)/(a-b))^(1/2))*(1/(a+b)*(b+a*co
s(d*x+c))/(cos(d*x+c)+1))^(1/2)*a^4*b+483*C*EllipticF((-1+cos(d*x+c))*((a-b)/(a+b))^(1/2)/sin(d*x+c),(-(a+b)/(
a-b))^(1/2))*(1/(a+b)*(b+a*cos(d*x+c))/(cos(d*x+c)+1))^(1/2)*a^3*b^2+189*C*EllipticE((-1+cos(d*x+c))*((a-b)/(a
+b))^(1/2)/sin(d*x+c),(-(a+b)/(a-b))^(1/2))*(1/(a+b)*(b+a*cos(d*x+c))/(cos(d*x+c)+1))^(1/2)*a^4*b-483*C*Ellipt
icE((-1+cos(d*x+c))*((a-b)/(a+b))^(1/2)/sin(d*x+c),(-(a+b)/(a-b))^(1/2))*(1/(a+b)*(b+a*cos(d*x+c))/(cos(d*x+c)
+1))^(1/2)*a^3*b^2+483*C*EllipticE((-1+cos(d*x+c))*((a-b)/(a+b))^(1/2)/sin(d*x+c),(-(a+b)/(a-b))^(1/2))*(1/(a+
b)*(b+a*cos(d*x+c))/(cos(d*x+c)+1))^(1/2)*a^2*b^3-10*A*((a-b)/(a+b))^(1/2)*sin(d*x+c)*b^5*(1/(cos(d*x+c)+1))^(
3/2)+279*A*EllipticF((-1+cos(d*x+c))*((a-b)/(a+b))^(1/2)/sin(d*x+c),(-(a+b)/(a-b))^(1/2))*(1/(a+b)*(b+a*cos(d*
x+c))/(cos(d*x+c)+1))^(1/2)*a^3*b^2-155*A*EllipticF((-1+cos(d*x+c))*((a-b)/(a+b))^(1/2)/sin(d*x+c),(-(a+b)/(a-
b))^(1/2))*(1/(a+b)*(b+a*cos(d*x+c))/(cos(d*x+c)+1))^(1/2)*a^2*b^3-10*A*EllipticF((-1+cos(d*x+c))*((a-b)/(a+b)
)^(1/2)/sin(d*x+c),(-(a+b)/(a-b))^(1/2))*(1/(a+b)*(b+a*cos(d*x+c))/(cos(d*x+c)+1))^(1/2)*a*b^4+147*A*(1/(a+b)*
(b+a*cos(d*x+c))/(cos(d*x+c)+1))^(1/2)*EllipticE((-1+cos(d*x+c))*((a-b)/(a+b))^(1/2)/sin(d*x+c),(-(a+b)/(a-b))
^(1/2))*a^4*b-279*A*(1/(a+b)*(b+a*cos(d*x+c))/(cos(d*x+c)+1))^(1/2)*EllipticE((-1+cos(d*x+c))*((a-b)/(a+b))^(1
/2)/sin(d*x+c),(-(a+b)/(a-b))^(1/2))*a^3*b^2+279*A*(1/(a+b)*(b+a*cos(d*x+c))/(cos(d*x+c)+1))^(1/2)*EllipticE((
-1+cos(d*x+c))*((a-b)/(a+b))^(1/2)/sin(d*x+c),(-(a+b)/(a-b))^(1/2))*a^2*b^3+10*A*(1/(a+b)*(b+a*cos(d*x+c))/(co
s(d*x+c)+1))^(1/2)*EllipticE((-1+cos(d*x+c))*((a-b)/(a+b))^(1/2)/sin(d*x+c),(-(a+b)/(a-b))^(1/2))*a*b^4)/a^2/(
(a-b)/(a+b))^(1/2)/(b+a*cos(d*x+c))/(1/(cos(d*x+c)+1))^(3/2)/sin(d*x+c)^6
________________________________________________________________________________________
Maxima [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate(cos(d*x+c)^(9/2)*(a+b*sec(d*x+c))^(5/2)*(A+B*sec(d*x+c)+C*sec(d*x+c)^2),x, algorithm="maxima")
[Out]
Timed out
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left ({\left (C b^{2} \cos \left (d x + c\right )^{4} \sec \left (d x + c\right )^{4} +{\left (2 \, C a b + B b^{2}\right )} \cos \left (d x + c\right )^{4} \sec \left (d x + c\right )^{3} + A a^{2} \cos \left (d x + c\right )^{4} +{\left (C a^{2} + 2 \, B a b + A b^{2}\right )} \cos \left (d x + c\right )^{4} \sec \left (d x + c\right )^{2} +{\left (B a^{2} + 2 \, A a b\right )} \cos \left (d x + c\right )^{4} \sec \left (d x + c\right )\right )} \sqrt{b \sec \left (d x + c\right ) + a} \sqrt{\cos \left (d x + c\right )}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate(cos(d*x+c)^(9/2)*(a+b*sec(d*x+c))^(5/2)*(A+B*sec(d*x+c)+C*sec(d*x+c)^2),x, algorithm="fricas")
[Out]
integral((C*b^2*cos(d*x + c)^4*sec(d*x + c)^4 + (2*C*a*b + B*b^2)*cos(d*x + c)^4*sec(d*x + c)^3 + A*a^2*cos(d*
x + c)^4 + (C*a^2 + 2*B*a*b + A*b^2)*cos(d*x + c)^4*sec(d*x + c)^2 + (B*a^2 + 2*A*a*b)*cos(d*x + c)^4*sec(d*x
+ c))*sqrt(b*sec(d*x + c) + a)*sqrt(cos(d*x + c)), x)
________________________________________________________________________________________
Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate(cos(d*x+c)**(9/2)*(a+b*sec(d*x+c))**(5/2)*(A+B*sec(d*x+c)+C*sec(d*x+c)**2),x)
[Out]
Timed out
________________________________________________________________________________________
Giac [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
integrate(cos(d*x+c)^(9/2)*(a+b*sec(d*x+c))^(5/2)*(A+B*sec(d*x+c)+C*sec(d*x+c)^2),x, algorithm="giac")
[Out]
Timed out